CalculationsPregunta 2 de 110
In the standard dwelling calculation, what is the minimum load to include for two required small-appliance branch circuits plus one laundry branch circuit, before any demand factor?
a.3,000 VA
b.4,500 VA
c.6,000 VA
d.1,500 VA
Explicación
Each small-appliance and laundry circuit is figured at 1,500 VA. Two small-appliance circuits (2 x 1,500 = 3,000) plus one laundry circuit (1,500) equals 4,500 VA.
Practica las 110 preguntas gratis — sin registro.
Preguntas relacionadas de este tema
- A single-family dwelling has 2,000 sq ft of habitable floor area. Using the standard calculation method at 3 VA per sq ft, what is the general lighting and general-use receptacle load before any demand factors?
- A dwelling has 7,200 VA general lighting, 3,000 VA small-appliance, and 1,500 VA laundry. Applying the standard demand factor (first 3,000 VA at 100%, remainder at 35%), what is the net general lighting load?
- Using the demand table for household electric ranges, what is the demand load for one 12-kW electric range in a dwelling (Column C, one appliance)?
- What is the demand load for two 12-kW household electric ranges served from one feeder (range demand table, Column C, two appliances)?
- A single household range is rated 16 kW. Using the 5% increase per kW over 12 kW rule on the 8-kW base, what is the demand load?
- A dwelling has one 4-kW electric clothes dryer. What value must be used as the dryer demand load in the service calculation?
Última revisión: · proceso editorial
Equipo Editorial de PrepPass · Verificado con Master Electrician Licensing Exam (NEC-based) · Cómo revisamos