Theory & DesignPregunta 85 de 110
An 80-kW load at 0.80 power factor is to be corrected to 0.95. How many kVAR of capacitance are required (tan 36.87 = 0.75, tan 18.19 = 0.329)?
a.33.7 kVAR
b.60 kVAR
c.48 kVAR
d.20 kVAR
Explicación
Qc = kW x (tan(theta1) - tan(theta2)) = 80 x (0.750 - 0.329) = 80 x 0.421 = 33.7 kVAR.
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