Systems & CodePregunta 52 de 110
A public toilet room fixture count is based on occupant load. If a code table requires one water closet per 40 occupants and the occupant load is 210, how many water closets are the minimum required?
a.4
b.5
c.7
d.6
Explicación
Divide occupants by the ratio and round up: 210 / 40 = 5.25, which rounds up to 6 water closets. Fixture counts always round up because you cannot install a fraction of a fixture and the code sets a minimum. The occupant load is typically split by sex before applying the ratio in many codes.
Referencia Legal: UPC §418.0Practica las 110 preguntas gratis — sin registro.
Preguntas relacionadas de este tema
- A sewage ejector serving fixtures below the sewer must discharge upward and then into the gravity building drain. What fitting protects the pump from gravity backflow when it is off?
- A medical gas distribution system has a working pressure of 50 psi. The installation acceptance test is performed at 1.5 times the working pressure. What is the required test pressure?
- A thermostatic mixing valve blends 140 F stored water with 60 F cold water to deliver 110 F tempered water at a public lavatory. Using a mass balance, what fraction of the delivered flow must be the 140 F hot water?
- An oil-water separator serves three garage floor drains each rated at 20 gpm. The code allows sizing at 75 percent of the total connected flow for diversity. What design flow sizes the separator?
- A laboratory discharges 10 gpm of acid waste that must be diluted with water at a 5-to-1 ratio (water to acid waste) before it enters the neutralizing tank. How much dilution water is required?
- An air admittance valve (AAV) is used to vent an island fixture. Which condition must be met for the AAV to be acceptable?
Última revisión: · proceso editorial
Equipo Editorial de PrepPass · Verificado con Master Plumber Licensing Exam (UPC/IPC-based) · Cómo revisamos